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One mole of N(2)H(4) loses ten moles of ...

One mole of `N_(2)H_(4)` loses ten moles of electrons to form a new compound `A`. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in `A`? (There is no change in the oxidation state of hydrogen.)

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The correct Answer is:
3
`N_(2)H_(4) overset("loss of" 10e^(-)) to Y`
Oxidation number of nitrogen in `N_(2)O_(4) =-2`
According to given information in the equation
`N_(2)H_(4) to N_(2)`
`therefore Y=N_(2)`
Y=+3
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