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CsBr has bcc like structures with edge l...

CsBr has bcc like structures with edge length `4.3Å`. The shortest inter ionic distance in between `Cs^(+)` and `Br^(-)` is:

Text Solution

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The correct Answer is:
3.72
For bcc structure, atomic radius, `r=sqrt(3)/4`a
`=sqrt(3)/4 xx 4.3 = 1.86 Å`
Since, r = half the distance between two nearest neighbouring atoms.
`therefore` Shortest interionic distance = `2 xx 1.86 = 3.72 Å`
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