Molybdenum forms body-centred cubic crystals whose density is `10.3 g cm^(-3)` . Calculate the edge length of the unit cell. The molar mass of Mo is `95.94 g "mol"^(-1)`.

Answer

314

Explanation

Given, bcc, i.e, Z=2
Crystal density `=10.3 g//cm^(3)`
M = 95.94 g/mol
Apply the formula,
Crystal density `=(Z xx M)/(V xx N_(A))`
`=10.3 =(2 xx 95.94)/(V xx 6.023 xx 10^(23))`
`therefore V=a^(3)`
`therefore a=(V)^(1//3)`
a = 313.9 pm