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The vapour pressure of pure benzene at a...

The vapour pressure of pure benzene at a certain temperature is `640 mm Hg`. A non-volatile solid weighing `2.175g` is added to `39.0g` of benzene. The vapour pressure of the solution is `600mm Hg`. What is the molar mass of the solid substance?

Text Solution

Verified by Experts

The correct Answer is:
65.25

According to Raoult.s law
`(P_(0)-P)/P^(@) = (w//m)/(w//m + W//M)`
Here, `P^(@) = 640 mm Hg, P= 600 mm Hg, w=2.175 g`
W= 39.0g M=78, m = Molecular weight of solute
Substituting the various values in the above equation `=(640-600)/640 = (2.175//m)/(2.175//m + 39//78)`
m = 65. 25 g
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