Home
Class 12
CHEMISTRY
An element X (Atomic mass = 25) exists a...

An element X (Atomic mass = 25) exists as X4 is benzene. 51g of saturated solution of X in benzene was added to 50.0 g of pure benzene. The resulting solution showed a depression of freezing point of 0.55 K. Find the solubility of X per 100 g of benzene. (Kf for benzene = 5.5 K kg `"mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
2
Let x g be the mass of element in 51.0 g of saturated solution.
Mass of benzene in 51.0 g of saturated solution
= 51.0 -x g
Total mass of benzene containing x g of solution
`=50+51 -x=(101-x)g`
`DeltaT_(f) = (1000 K_(f)W_(B))/(M_(B)W_(A)) = (1000 xx 5.5 xx x)/(4 xx 25 xx (101 -x))`
=0.55 (given)
`rArr x=1.0 g`
Hence, solubility
`=(W_(B) xx 100)/W_(A) =1/(51-1) xx 100 = 2.0 g`
Promotional Banner

Topper's Solved these Questions

  • CHAPTERWISE NUMERIC/INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER-17 ELECTROCHEMISTRY|15 Videos

  • CHAPTERWISE NUMERIC/INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER-18 CHEMICAL KINETICS|15 Videos

  • CHAPTERWISE NUMERIC/INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER-15 THE SOLID STATE|15 Videos

  • BIOMOLECULES

    DISHA PUBLICATION|Exercise Exercise - 2 : Concept Applicator|30 Videos

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    DISHA PUBLICATION|Exercise EXERCISE-2: CONCEPT APPLICATOR|30 Videos

Similar Questions

Explore conceptually related problems

A solution of 0.643 g of an organic compound in 50 mL of benzene (density 0.879 g//mL ) lowered its freezing point from 5.51^(@)C to 5.03^(@)C . Calculate the molecular weight of solid. (K_(f) for benzene is 5.12 K mol^(-1) kg )

The freezing point of benzene decreases by 0.45^(@)C when 0.2 g of acetic acid is added to 20 g of benzene. IF acetic acid associates to form a dimer in benzene, percentage association of acetic acid in benzene will be (K_(f) "for benzene" = 5.12 K kg mol^(-1))

The boiling a point of benzene is 353.23K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. K_(b) for benzene is 2.53 K kg mol^(-1) .

(a) State Raoult's law for a solution containing volatile components. How does Raoult' s law become a special case of Henry's law? (b) 1.00 g of a non-electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.40 K. Find the molar mass of the solute. (K_(f)" for benzene "=5.12 kg mol^(-1))

When 2.0g of a non-volatile solute was dissolved in 90 gm of benzene, the boiling point of benzene is raised by 0.88K. Which of the following may be the solute? K_(b) for benzene =2.53 K kg mol^(-1))