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Calculate the molality of 1 litre soluti...

Calculate the molality of 1 litre solution of 93% `H_(2)SO_(4) ("weight"//"volume")`. The density of solution is 1.84 g `mL^(-1)`.

Text Solution

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The correct Answer is:
10.43
Mass of `H_(2)SO_(4)` in 100mL of 93% `H_(2)SO_(4)` solution = 93 g
`therefore` Mass of `H_(2)SO_(4)` in 1000 ml of the `H_(2)SO_(4)` solution = 930 g
Mass of 1000 ml `H_(2)SO_(4)` solution
`=1000 xx 1.84 = 1840`g
Mass of water in 1000 ml of solution
=1840 - 930 = 910 g
Moles of `H_(2)SO_(4) = (wt. of H_(2)SO_(4))/(Mol.wt of H_(2)SO_(4)) = 930/98`
`therefore` Moles of `H_(2)SO_(4)` in 1 kg of water
`=930/98 xx 1000/910 = 10.43 mol kg^(-1)`
`therefore` Molality of 1 litre solution = 10.43
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