The standard reduction potential of a silver chloride electrode (metal -sparingly soluble salt electrode) is `0.209V` and for silver electrode is `0.80V`. If the moles of `AgCl` that can dissolve in `10L` of a `0.01M NaCl` solution is represented as `10^(-z)` then find the value of `z`.

Answer

7

Explanation

`E_(Cl^(-)//AgCl//Ag)^(@) =E_(Ag//Ag)^(@) + 1(0.0591)/1 log K_(sp)`
`0.209 = 0.80 + (0.0591)/1 log K_(sp)`
`K_(sp) = 10^(-10)`, let solubility of AgCl in 0.01 M solution is x
`10^(-10) =x(x+0.01)`
`x=10^(-8)`
`therefore` Molecules of AgCl dissolved in 10 L `=10^(-8) xx 10 = 10^(-7)`