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The standard Gibbs energy for the given ...

The standard Gibbs energy for the given cell reaction is `KJmol^(-1)` at 298 K is :
`Zn(s)+CU^(2+) (aq) rightarrow Zn^(2+) (aq) + Cu(s)`
`E^(@)= 2V at 298 K`
(Friday's constant , `F = 96000 C mol^-1`)

Text Solution

Verified by Experts

The correct Answer is:
`-384`
`DeltaG^(@) = -nFE_("cell")^(@)`
`=-2 xx (96000) xx 2V = -384000` J/mol
`=-384` kJ/mol
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