The instataneous rate of disappearance of the `MnO_(4)^(-)` ion in the following reaction is `4.56 xx 10^(-3) Ms^(-1)`. Then the rate of appearance of `I_(2)` is :
`2MnO_(4)^(-)+10 I^(-)+16H^(+) rarr 2Mn^(2+)+5I_(2)+8H_(2)O`

Answer

0.0114

Explanation

`(dMnO_(4)^(-))/(dt) = 4.56 xx 10^(-3) Ms^(-1)` (given)
From the reaction given,
`-1/2 (dMnO_(4)^(-))/(dt) =(4.56 xx 10^(-3))/2 Ms^(-1)`
`-1/2 (dMnO_(4)^(-))/(dt) = 1/5 (dI_(2))/(dt)`
`therefore -5/2 (dMnO_(4)^(-))/(dt) = (dI_(2))/2`
On substituting the given value
`therefore -5/2 (dMnO_(4)^(-))/2 = (dI_(2))/(dt)`
On substituting the given value
`therefore (dI_(2))/(dt) = (4.56 xx 10^(-3) xx 5)/2 = 1.14 xx 10^(-2) M//s`
`=0.0114 Ms^(-1)`