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Differentiate y = (x^(3/4) sqrt(x^2 + 1)...

Differentiate `y = (x^(3/4) sqrt(x^2 + 1))/((3x+2)^5)`.

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The correct Answer is:
Therefore, `(dy)/(dx) = y' = (x^(3/4) sqrt(x^(2) +1) /((3x+2)^(5) ) [ (3)/(4x) + (x)/(x^2 + 1) - (15)/(3x+2)]`
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