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A rod of length 2l is broken into two pi...

A rod of length 2l is broken into two pieces at random. The probability density function of the shorter of the two pieces is
`f(x)={{:(1/l, 0 lt x ge l), (0, l le x lt 2l):}`
The mean and variance of the shorter of the two pieces are respectively

A

`(l)/(2), (l^(2))/(3)`

B

`(l)/(2), (l^(2))/(6)`

C

`l, (t^(2))/(12)`

D

`(l)/(2), (t^(2))/(12)`

Text Solution

Verified by Experts

The correct Answer is:
D
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