Verify whether the line ` (x-3)/(-4)=(y-4)/(-7)=(z+3)/(12) ` lies in the plane 5x – y +z = 8.

Check whether the line (x-1)/(4)=(y+2)/(5)=(z-7)/(6) lines in the plane 3x+2y+z=6 .

For the line (x-6)/(6)=(y+4)/(4)=(z-4)/(8),

Column I, Column II Image of the point (3,5,7) in the plane 2x+y+z=-18 is, p. (-1,1,-1) The point of intersection of the line (x-2)/(-3)=(y-1)/(-2)=(z-3)/2 and the plane 2x+y-z=3 is, q. (-21 ,-7,-5) The foot of the perpendicular from the point (1,1,2) to the plane 2x-2y+4z+5=0 is, r. (5/2,2/3,8/3) The intersection point of the lines (x-1)/2=(y-2)/3=(z-3)/4a n d(x-4)/5=(y-1)/2=z is, s. (-1/(12),(25)/(12),(-2)/(12))

Find the angle between the line (x-2)/(3)=(y-1)/(-1)=(z-3)/(2)" and the plane "3x+4y+z+5=0.

If the line (x-2)/(3)=(y-1)/(-5)=(z+2)/(2)" lies in the plane "x+3y-az+beta=0" then "(alpha,beta) is

Find the equation of the projection of the line (x-1)/2=(y+1)/(-1)=(z-3)/4 on the plane x+2y+z=9.

The distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/2=(y+1)/4=(z-2)/12 and the plane x-y+z=5 is

Find the angle between the line (x-1)/3=(y-1)/2=(z-1)/4 and the plane 2x+y-3z+4=0.

Show that the disease of the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/12 and the plane (x-y+z=5) from the point (-1,-5,-10) is 13 units.