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If n is odd then int(0)^(pi//2)sin^(n)x ...

If n is odd then `int_(0)^(pi//2)sin^(n)x dx ` is

A

`(n)/(n-1).(n-2)/(n-3).(n-4)/(n-5)...pi/2`

B

`(n-1)/(n).(n-3)/(n-2).(n-5)/(n-4)...pi/2`

C

`(n)/(n-1).(n-2)/(n-3).(n-4)/(n-5)...3/(2).1`

D

`(n-1)/(n).(n-3)/(n-2).(n-5)/(n-4)...2/(3).1`

Text Solution

Verified by Experts

The correct Answer is:
D
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