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(dy)/(dx)+(y)/(xlogx)=(sin2x)/(logx)...

`(dy)/(dx)+(y)/(xlogx)=(sin2x)/(logx)`

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Solve the following linear differential equation (dy)/(dx)+(y)/(x log x)=(sin 2x)/(log x)

x(dy)/(dx)+y=xlogx

The integrating factor of (dy)/(dx)+(1)/(xlogx)y= (2)/(x^(2)) is :

(dy)/(dx)=sin (x+y)

x(dy)/(dx)+2y-x^(2)logx=0

Solve (dy)/(dx)+(y^(2))/(x^(2))=(y)/(x)

The general solution of x((dy)/(dx))+(logx)y=x^(-1/2logx) is

(dy)/(dx) = sin^(-1)x

(dy)/(dx) + 2y tan x = sin x