If the planes 2x + 3y - z + 5 = 0, x + 2y – kz + 7 = 0 are perpendicular then k=

Find the equation of the plane through the intersection of the planes 2x - 3y + z - = 0 and x - y + z + 1 = 0 and perpendicular to the plane x + 2y - 3z + 6 = 0.

Plane passing through the intersection of the planes x + 2y + z - 1 = 0 and 2x + y + 3z - 2 = 0 and perpendicular to the plane x + y + z - 1 = 0 and x + ky + 3z - 1 = 0. Then the value of k is

Plane passing through the intersection of the planes x + 2y + z- 1 = 0 and 2x + y + 3z - 2 = 0 and perpendicular to the plane x + y + z - 1 = 0 and x + ky + 3z - 1 = 0. Then the value of k is

Plane passing through the intersection of the planes x + 2y + 2-1 = 0 and 2x + y + 3z - 2 = 0 and perpendicular to the plane x + y + z-1= 0 and x + ky + 3z - 1 = 0. Then the value of k is

Find the equation of the plane passing through the intersection of the planes 2x - 3y + z-4 = O and x-y + 2 + 1 = 0 and perpendicular to the plane x + 2y - 3z + 6 = 0.

The equation of the plane passing through the line of intersection of the planes x + y + 2z = 1,2x + 3y + 4z = 7, and perpendicular to the plane x - 5y + 3z = 5 is given by:

Find the value of 'k' for which the plane : 3x - 6y - 2z = 7 and 2x + y - kz = 3 are perpendicular to each other.