Let P and Q be points of the ellipse `16 x^(2) +25y^(2) = 400` so that `PQ = 96//25` and P and Q lie above major axis. Circle drawn with PQ as diameter touch major axis at positive focus, then the value of slope m of PQ is

Let "P" ,"Q" be points of the ellipse " 16x^(2)+25y^(2)=400 " ,so that " PQ=96/25 " and "P" ,"Q" lie above major axis. The circle drawn with "PQ" as diameter touches major axis at positive focus .If "m" is slope of "PQ" then the value of " 1/|m| " is

The tangent at any point on the ellipse 16x^(2) + 25^(2) = 400 meets the tangents at the ends of the major axis at T_(1) and T_(2) . The circle on T_(1)T_(2) as diameter passes through

The tangent at any point on the ellipse 16x^(2)+25y^(2) = 400 meets the tangents at the ends of the major axis at T_(1) and T_(2) . The circle on T_(1)T_(2) as diameter passes through

The line x=2y intersects the ellipse (x^(2))/4+y^(2)=1 at the points P and Q . The equation of the circle with PQ as diameter is

A focal chord perpendicular to major axis of the ellipse 9x^(2)+5y^(2)=45 cuts the curve at P and Q then length of PQ is

Let P and Q be points on the line joining A(-2, 5) and B(3, 1) such that AP = PQ = QB. If mid-point of PQ is (a, b), then the value of (b)/(a) is

If 'P' be a moving point on the ellipse (x^(2))/(25)+(y^(2))/(16)=1 in such a way that tangent at 'P' intersect x=(25)/(3) at Q then circle on PQ as diameter passes through a fixed point.Find that fixed point.