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ZnO crystal on heating acquires the form...

ZnO crystal on heating acquires the formula `Zn_(1+x)` O. Give reason.

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ZnO crystals on heating acquires the formuls Zn_(1+x)O . Or There is an increase in conductivity when silicon doped with phosphorus. Give reason.

ZnO crystals on heating acquires the formuls Zn_(1+x)O . Or There is an increase in conductivity when silicon doped with phosphorus. Give reason.

ZnO crystals on heating acquires the formuls Zn(1+x)O . Or There is an increase in conductivity when silicon doped with phosphorus. Give reason.

F centre is an example of metal excess defect due to the presence of extra cations at interstitial sites. Zinc oxide is white in colour at room temperature, on heating it loses oxygen and turns yellow. ZnO overset("Heat")toZn^(2+)+(1)/(2)O_(2)+2e^(-) Now there is excess of zinc in the crystal and its formula becomes Zn_(1+x) O. the excess of Zn^(2+) ions move to interstitial sites and the electrons to neighbouring interstitial sites. There are many solids which are difficult to prepare in the stiochiometric composition and contain less amount of the metal as compared to stiochiometric proportion. a typical example of this type is FeO which is mostly found with a composition of Fe_(0.95) . it may actually range from Fe_(0.96) O. Q. In Fe_(0.95) O:

Analyses shows that FeO has a non-stoichiometric composition with formula Fe_(0.95)O_(1.00) . Give reason.

Analyses shows that FeO has a non-stoichiometric composition with formula Fe_(0.95)O_(1.00) . Give reason.

Analyses shows that FeO has a non-stoichiometric composition with formula Fe_(0.95)O_(1.00) . Give reason.

Analyses shows that FeO has a non-stoichiometric composition with formula Fe_(0.95)O_(1.00) . Give reason.

Zn on heating with barium carbonate gives: