How many grams of `KBr` can be added to `1L` of `0.12 M` solution of `AgNO_(3)` just to start the precipitation of `AgBr. (Mw "of" KBr = 120, K_(sp) of AgBr = 10^(-13))`

How many grams of potassium bromide (KBr) be added to 1 L of 0.05 M solution of silver nitrate just to start the precipitation of silver bromide ?

The minimum mass of NaBr which should be added in 200 ml of 0.0004M-AgNO_(3) solution just to start precipitation of AgBr.K_(sp) of AgBr=4xx10^(-13)(Br=80)

The minimum mass of NaBr which should be added in 200 ml of 0.0004M-AgNO_(3) solution just to start precipitation of AgBr.K_(sp) of AgBr=4xx10^(-13)(Br=80)

K_(sp) of AgBr at room temperature is 5 times 10^(-13)M^(2) . The quantity of KBr (Mol. mass = 120 g/mol) to be added to 1 litre of a 0.05 M solution of AgNO_(3) at room temp. to start the precipitation of AgBr is

Solubility product of silver bromide is 5.0xx10^(-13) . The quantity of potassium bromide (molar mass taken as 120g mol^(-1) ) to be added to 1 L of 0.05 M solution of silver nitrate to start the precipitation of AgBr is