If the wavelength of the first member of Balmer series of hydrogen spectrum is `6564A^(@)` , the wavelength of second member of Balmer series will be:

If the wavelength of first member of Balmer series of hydrogen spectrum is 6564 A^(@) . The wavelength of second member of Balmer series will be :

If the wavelength of first member of Balmer series of hydrogen spectrum is 6564 A^(@) . The wavelength of second member of Balmer series will be :

If the wavelength of the first member of Balmer series of hydrogen spectrum is 6563Å , then the wavelength of second member of Balmer series will be

If the wavelength of the first member of Blmer series of hydrogen spectrum is 6563Å A, then the wavelength of second member of Blamer series will be

If the wavelength of the first member of Balmer series in hydrogen spectrum is 6563 Å, calculate the wavelength of the first member of Lymen series in the same spectrum.

Calculate the value of Rydberg constant if the wavelength of the first member of Balmer series in the hydrogen spectrum is 6563 Å. Also find the wavelength of the first member of Lyman series in the same spectrum.

The wavelength of first member of Balmer series in the hydrogen spectrum is 6563 oversetcircA . Calculate the wavelength of second member of Balmer series.

Calculate the wavelength of the first line in the Balmer series of hydrogen spectrum

The wavelength of the first lime of the Lyman series of hydrogen is 121.6 nm. The wavelength of the second member of the Balmer series is