`underset(x to oo)lim ((x+1)(2x+3))/((x+2)(3x+4))=`

underset(x to oo)lim (3x^(2)+5x+2)/(2x^(2)-3x+1)=

Find the limits : underset(x to oo)lim ((1+x)/(2+x))^((1-sqrtx)//(1-x)) (b) underset(x to oo)lim ((x^(2)+2x-1)/(2x^(2)-3x-2))^((2x+1)//(x-1))

The value of the limit underset(x to oo)lim ((x^(2)-1)/(x^(2)+1))^(x^(2)) equal to

underset(x to oo)lim (2x+7)/(x^(2)+5x+4)=

underset(x to oo)lim (3x^(3)+x^(2)-1)/(x^(2)-x+7)=

underset(x to oo)lim (-x^(3)+8)/(2x^(2)+5x+7)=

Evaluate underset(x to -oo)lim(sqrt(x^(2)+3x+1))/(2x+4)

Evaluate underset(x to -oo)lim(sqrt(x^(2)+3x+1))/(2x+4)

underset(x to oo)lim ((x^(3))/(3x^(2)-1)-(x^(2))/(3x+1))=