In the equation `(x-p)/q+(x-q)/p=q/(x-p)+p/(x-q),x ` is not equal to

If the roots of the equation 1/(x+p)+1/(x+q)=1/r, (x ne -p, x ne -q, r ne 0) are equal in magnitude but opposite in sign, then p + q is equal to :

If the roots of the equation (1)/(x+p)+(1)/(x+q)=(1)/(r ),(x ne -p, x ne -q, r ne 0) are equal in magnitude but opposite in sign, then p+q is equal to

solve x:(p)/(x-q)+(q)/(x-p)=2;x!=p,q

If p ,q are real p!=q , then show that the roots of the equation (p-q)x^2+5(p+q)x-2(p-q)=0 are real and unequal.

If p,q are real p!=q, then show that the roots of the equation (p-q)x^(2)+5(p+q)x-2(p-q)=0 are real and unequal.

If the roots of the equation p(q-r)x^2+q(r-p)x+r(p-q)=0 be equal ,show that 1/p+1/r=2/q

If the roots of the equation p(q-r)x^2+q(r-p)x+r(p-q)=0 be equal, show that 1/p+1/r=2/q .

If the roots of the equation (q-r)x^(2)+(r-p)x+p-q=0 are equal, then show that p, q and r are in A.P.