A bullet of mass `'x'` moves with a velocity `y`, hits a wooden block of mass `z` at rest and gets embedded in it. After collision, the wooden block and bullet moves with a velocity

A bullet of mass x moves with a velocity y, hits a wooden block of mass z, at rest and gets embedded in it. After collision if the wooden block with bullet in it moves the velocity is

A bullet of mass m moving with velocity v strikes a block of mass M at rest and gets embedded into it. The kinetic energy of the composite block will be

A bullet of mass m moving with velocity v strikes a block of mass M at rest and gets embedded into it. The kinetic energy of the composite block will be

A bullet of mass m, moving with a velocity u hits a wooden block of mass M and gets embedded. Assuming that the wooden block can move freely, show that, the loss of kinetic energy =1/2 (mM)/(m+M) u^2 .

A 50 g bullet moving with velocity 10 m / s strikes a block of mass 950 g at rest and gets embedded in it. The loss in kinetic energy will be

A bullet of mass 20 g moving with a speed of 500ms^(-1 ) strikes a wooden block of mass 1 kg and gets embedded in it. Find the speed with which block moves along with the bullet.