If `180^(@) lt theta lt 270^(@) , sin theta =-3//5` , then ` cos theta //2=`

If 180^(@) lt theta lt 270^(@), sin theta =-4//5 , " then " tan theta //2=

If 180^(@) lt theta lt 270^(@) , tan theta = 5//12 , " then " cos 3 theta =

If 180^(@) lt theta lt 270^(@) and sin theta = -5//13 then 5 cot^(2) theta + 12 tan theta + 13 "cosec" theta =

If 90^(@) lt theta lt 180^(@) , cos theta =-12//13 , then sin 2 theta =

If 180^(@)ltthetalt270^(@),tan theta=5/12 ,then cos3 theta=

If cos theta =(5)/(13) and 270 ^(@) lt theta lt 360^(@) , evaluate sin ( theta //2) and cos ( theta//2)

If theta^(@) lt theta lt 90^(@) and (sin theta)/(cos theta) + (cos theta)/(sin theta)=2 , then which of the following is equal to theta ?