Two particles A and B having equal charges are placed at distance d apart. A third charged particle placed on the perpendicular bisector at a distance x will experience the maximum Coulomb’s force when :

Two equal point charges A and B are R distance apart. A third point charge placed on the perpendicular bisector at a disttance d from the centre will experience maximum electrostatic force when

Two identical point charges are kept at a distance d. A third point charge is placed on the perpendicular bisector of the two charges at a distance x. Show that the third charge will experience maximum force when x=(d)/(2sqrt2) .

Two equal charges q are placed at a distance of 2a and a third charge -2q is placed at the midpoint. The potential energy of the system is

Two point charges +q and -q are placed a distance x apart. A third charge is so placed that at the three charges are in equilibrium. Then

Two charged particles are a distance 1 mm apart. Find the minimum Coulomb force between them.

Two free charges q and 4q are placed at a distance d apart A third charge Q is placed between them at a distance x from charge q such that the system is in equilibrium. Then

Two point charges +q and -q are placed a distance x apart. A third charge is so placed that al the three charges are in equilibrium. Then

Two charges are placed at a distance apart if a glas slab is placed between them force between them will