An engine can pull four coaches at a maximum speed of `20ms^-1`. The mass of the engine is twice the mass of every coach. Assuming resistive forces to be proportional to the weight, approximate maximum speeds of the engine, when it pulls `12` and `6` coaches, are

An engine can move at the speed of 20/3 m/s without any wagon attached and reduction in the speed of the train is directly proportional to the square root of the number of wagons attached to the engine. When there are 9 wagons attached its speed is 5 m/s. The greatest number of wagons with which the engine can move is :

Assume the aerodynamic drag force on a car is proportional to its speed. If the power output from the engine is doubled, then the maximum speed of the car

An engine is pulling a train of mass m on a level track at a uniform speed u . The resistive froce offered per unit mass is f .

An engine is pulling a train of mass m on a level track at a uniform speed u . The resistive froce offered per unit mass is f .

An engine is pulling a train of mass m on a level track at a uniform speed u . The resistive froce offered per unit mass is f .

A car can pull a trailer of twice its mass up a certain slope at a maximum speed V. Without the trailer the maximum speed of the car, up the same slope is 2 V. The resistance to the motion is proportional to mass and square of speed. If the car (without trailer) starts to move down the same slope, with its engine shut off, prove that eventually it will acquire a constant speed. Find this speed.

A car can pull a trailer of twice its mass up a certain slope at a maximum speed v=1m//s . Without the trailer the maximum speed of the car up the same slope is 2v . The resistance to the motion is proportinal to mass and square of speed. If the car (without trailer) starts to move down the same slope, with its engine shut off, eventually it will acquire a constant speed v_(t) , then find v_(t)^(2) (in m^(2)//s^(2) )

A car can pull a trailer of twice its mass up a certain slope at a maximum speed v=1m//s . Without the trailer the maximum speed of the car up the same slope is 2v . The resistance to the motion is proportinal to mass and square of speed. If the car (without trailer) starts to move down the same slope, with its engine shut off, eventually it will acquire a constant speed v_(t) , then find v_(t)^(2) (in m^(2)//s^(2) )