Two waves are given as `y_1=3A cos (omegat-kx)` and `y_2=A cos (3omegat-3kx)` . Amplitude of resultant wave will be ____

On the superposition of the two waves given as y_1=A_0 sin( omegat-kx) and y_2=A_0 cos ( omega t -kx+(pi)/6) , the resultant amplitude of oscillations will be

On the superposition of the two waves given as y_1=A_0 sin( omegat-kx) and y_2=A_0 cos ( omega t -kx+(pi)/6) , the resultant amplitude of oscillations will be

Two waves are given by y_(1)=asin(omegat-kx) and y_(2)=a cos(omegat-kx) . The phase difference between the two waves is -

Two waves are given by y_(1)=asin(omegat-kx) and y_(2)=a cos(omegat-kx) . The phase difference between the two waves is -

Two waves are given by y_(1)=asin(omegat-kx) and y_(2)=a cos(omegat-kx) . The phase difference between the two waves is -

The displacement of two interfering light waves are given by y_(1)=3 sinomegat,y_(2)=4 sin(omegat+pi//2) . The amplitude of the resultant wave is

Two waves represented by y=asin(omegat-kx) and y=acos(omegat-kx) are superposed. The resultant wave will have an amplitude.

Two waves represented by y=asin(omegat-kx) and y=acos(omegat-kx) are superposed. The resultant wave will have an amplitude.

Two waves represented by y=asin(omegat-kx) and y=acos(omegat-kx) are superposed. The resultant wave will have an amplitude.

The displacement of the interfering light waves are y_1 = 4 sin omegat and y_2 = 3 sin (omegat + pi//2) . The amplitude of the resultant wave is