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3^(1)+3^(2)+3^(3)+...+3^(n)=(3(3^(n)-1))...

3^(1)+3^(2)+3^(3)+...+3^(n)=(3(3^(n)-1))/(2)

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1^(3)+2^(3)+3^(3)+. . .+n^(3)=((n(n+1))/(2))^(2) .

1^(3)+2^(3)+3^(3)+....+n^(3)=((n(n+1))/(2))^(2)