" find "Delta" if "a=6,b=3,cos(A-B)=4/5

In Delta ABC, if a = 6, b=3 and cos (A-B) = (4)/(5) " then " angle C =

In DeltaABC, if a =5,b=4 and cos (A-B)=31/32 ,then the perimeter of triangle is

If in a /_ABC,a=6,b=3 and cos(A-B)=(4)/(5) then find its area.

In DeltaABC , If in a DeltaABC , a = 6, b = 3 and cos(A-B)=4/5 , find its area.

In Delta ABC , a= 6 ,b=3 and cos (A-B) = 4/5 .Then are of triangle is

(i) If a:b:c= 2:3:4 and s=27 inches, find the area of the triangle ABC. (ii) If in a triangle ABC, a=6, b=3 and cos(A-B) =4/5 then find its area.

ABC is a triangle where a=6, b=3 and cos(A-B)=4/5 (i) Area of the triangle ABC (in sq. units) is-

ABC is a triangle where a=6, b=3 and cos(A-B)=4/5 Value of angle C is-

In Delta ABC , if : a = 6, b = 3, cos (A - B) = 4//5 , then : its area =