`intc o s e c2y dy+intsec2x dx=0`

Evaluate: (i) intsec^4 2x\ dx (ii) intcos e c^4\ 3x\ dx

If intsec2x dx=f{g(x)}+c then

2e^(x+2y) dx -3dy =0

The solution of e^(2x-3y)dx+e^(2y-3x)dy=0 is

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as Solution of the differential equation (dy)/(dx)=e^(3x-2y)+x^2e^(-2y) is (e^(2y))/(2)=(e^(3x))/(3)+(x^2)/(2)+C Reason (R) : (dy)/(dx)=e^(3x-2y)+x^2e^(-2y) (dy)/(dx)=e^(-2y)(e^(3x)+x^2) separating the variables e^(2y)dy=(e^(3x)+x^2)dx int e^(2y)dy=int(e^(3x)+x^2)dx (e^(2y))/(2)=(e^(3x))/(3)+(x^3)/(3)+C .

The solution of dx + x dy = e^(-y) sec^(2) y dy is

(dy)/(dx) + 2y = e ^(-2x) sinx , given that y=0 when x = 0

Solve the following differential equation: \ cos e c\ xlogy(dy)/(dx)+\ x^2y^2=0

y(2x y+e^x)dx-e^x dy=0