A battery of emf `12V` and internal resistance `2 Omega` is connected two a `4 Omega` resistor. Show that the a voltmeter when placed across cell and across the resistor in turn given the same reading

A battery of internal resistance 3Omega is connected to 20Omega resistor and the potential difference across the resistor is 10V. If another resistor 30Omega is connected in series with the first resistor and battery is again connectecl to the combination, then calculate the e.m.f and terminal potential difference across the combination..

A battery of emf 1.4 V and internal resistance 2 Omega is connected to a resistor of 100 omega resistance through an ammeter. This resistance of the ammeter is 4//3 Omega . A voltmeter has also been connected to find the potential difference across the resistor. a. Draw the circuit diagram. b. The ammeter reads 0.02 A . What is the resistance of the voltmeter? c. The voltmeter reads 1.1 V . What is the error in the reading?

A battery of emf 1.4 V and internal resistance 2 Omega is connected to a resistor of 100 omega resistance through an ammeter. This resistance of the ammeter is 4//3 Omega . A voltmeter has also been connected to find the potential difference across the resistor. a. Draw the circuit diagram. b. The ammeter reads 0.02 A . What is the resistance of the voltmeter? c. The voltmeter reads 1.1 V . What is the error in the reading?

A battery of emf 1.4V and interna! resistance 2Omega is connected to a resistor of 100Omega resistance through an ammeter. The resistance of ammeter is 4/3Omega a voltmeter has also been connected to find the potential difference across the resistor. The voltmeter reads 1.10V. What is the error in the reading ?

A battery of emf 1.4V and interna! resistance 2Omega is connected to a resistor of 100Omega resistance through an ammeter. The resistance of ammeter is 4/3Omega a voltmeter has also been connected to find the potential difference across the resistor. The ammeter reads 0.02 A. What is the resistance of voltmeter.

A battery of EMF 1.4 V and internal resistance 2Omega is connected to resistor of 100Omega resistance through an ammeter. The resistance of the ammeter is (4)/(3)Omega . A voltmeter is also connected to find potential difference across resistor. The ammeter reacds 0.02 A if resistance of voltmeter is 100x then x is

Two cells of emf 3 V and 2 V and internal resistances 1.5 Omega and 1 Omega respectively are connected in parallel across 3 Omega resistor such that they tend to send current through resistor in the same direction. Calculate potential difference across 3 Omega resistor.