The equation of tangent to the curve `x=(1)/(t), y=t-(1)/(t)` at t=2 is

The equation of normal to the curve x=(1)/(t), y=t-(1)/(t)" at "t=2 is

The equation of the tangent to the curve x = (t - 1)/(t + 1), y = (t + 1)/(t - 1) at t = 2 is a) x + 9y - 6 = 0 b) 9x - y - 6 = 0 c) 9x + y + 6 = 0 d) 9x + y - 6 = 0

The slope of the tangent to the curve x =1/t, y =t - t/t , at t=2 is ………….

The equation of tangent to the curve x=a cos^(3)t ,y=a sin^(3) t at 't' is

The equation of tangent to the curve x=a cos^(3)t ,y=a sin^(3) t at 't' is

Find the equation of tangent to the curve x=sin3t , y=cos2t\ \ at t=pi/4

Write the equation of a tangent to the curve x=t, y=t^2 and z=t^3 at its point M(1, 1, 1): (t=1) .

Write the equation of a tangent to the curve x=t, y=t^2 and z=t^3 at its point M(1, 1, 1): (t=1) .

Write the equation of a tangent to the curve x=t, y=t^2 and z=t^3 at its point M(1, 1, 1): (t=1) .