pH of 0.1 M `Na_2HPO_4` and 0.2 M `NaH_2PO_4` are respectively : (`pK_a` for `H_3PO_4` are 2.2,7.2,12.0)

pH of 0.1M Na_(2)HPO_(4) and 0.2M NaH_(2)PO_(4) are respectively: (pK_(a)"for" H_(3)PO_(4) are 2.12, 7.21 and 12.0 for respective dissociation to H_2PO_(4)^(-), HPO_(4)^(2-) and PO_(4)^(3-)) :

pH of 0.1M Na_(2)HPO_(4) and 0.2M NaH_(2)PO_(4) are respectively: (pK_(a)"for" H_(3)PO_(4) are 2.12, 7.21 and 12.0 for respective dissociation to HPO_(4)^(2-), HPO_(4)^(-) and PO_(4)^(3-)) :

Calculate pH a) NaH_(2)PO_(4) b) Na_(2)HPO_(4) respectively, for H_(3)PO_(4) pKa_(1) = 2.25, pKa_(2) = 7.20, pKa_(3) = 12.37 )

What will be the pH of a solution formed by mixing 10 ml 0.1 M NaH_(2)PO_(4) and 15 mL 0.1 M Na_(2)HPO_(4) ? ["Given: for "H_(3)PO_(4)Pk_(a_(1))=2.12, Pk_(a_(2))=7.2]

What will be the pH of a solution formed by mixing 10 ml 0.1 M NaH_(2)PO_(4) and 15 mL 0.1 M Na_(2)HPO_(4) ? ["Given: for "H_(3)PO_(4)pK_(a_(1))=2.12, pK_(a_(2))=7.2]

A buffer solution 0.04 M in Na_2HPO_4 and 0.02 M in Na_3 PO_4 is prepared. The electrolytic oxidation of 1.0 milli -mole of the organic compound RNHOH is carried out in 100 mL of the buffer. The reaction is RNHOH +H_2O to RNO_2 +4H ^(+) + 4e ^(-) The approximate pH of solution after the oxidation is complete is: [Given : for H_3O PO_4, pK_(a_1) =7.20 , pK_(a_2) =12]

A buffer solution of 0.080M Na_(2)HPO_(4) and 0.020 M Na_(3)PO_(4) is prepared. The electrolytic oxidation of 1.0 mmol RNHOH is carried out in 100mL buffer to give RNHOH + H_(2)O rarr RNO_(2) + 4H^(o+) + 4e^(-) Calculate approximate pH of the solution after oxidation is complete pK_(a_(2)), pK_(a_(2)) , and pK_(a_(3)) of H_(3)PO_(4) are 2.12,7.20 , and 12.0 , respectively.