500mL `M/100 h_(2)SO_(4)` विलयन बनाने के लिये कितने mg `H_(2)SO_(4)` की आवश्यकता होगी।

Explanation

`M = 1/100 mol L^(-)" , "M_(A)(H_(2)SO_(4)) = 98`
`V_(sol) mL = 500 mL" , "W_(A)?`
`M = W_(A)/M_(A) xx 1000/(V_(sol) mL)`
`1/100 = W_(A)/98 xx 1000/500`
`W_(A) = (98 xx 5)/1000 g`
` = 0.49 g`
`0.49 g H_(2)SO_(4) = 0.49 g xx (1000 mg)/(1 g)`
` = 490 mg`