[" Q6.If "/_ABC" is an isosceles triangle such that "AB=AC" ,an altitude "AD" from "A" is "],[" drawn on "BC" .Show that AD bisects "BC" ."]

If Delta ABC is an isosceles triangle such that AB=AC, then altitude AD from A on BC bisects BC( Fig.43)

In an isosceles triangle ABC, if AB=AC=13cm and the altitude from A on BC is 5cm, find BC.

In an isosceles triangle ABC, if AB = AC = 25 cm and altitude from A on BC is 24 cm, find BC.

In an isosceles triangle altitude from the vertex bisects the base.GIVEN: An isosceles triangle ABC such that AB=AC and an altitude AD from A on side BC. TO PROVE : D bisects BC i.e.BD=DC .Figure

DeltaABC is an isosceles triangles with AB = AC = 10 cm,AD =8 cm M is the median on BC from A. The length of BC is

AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that AD bisects BC.

AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that AD bisects BC.

triangle ABC is an isosceles triangle with AB = AC= 15 cm and altitude from A to BC is 12 cm. The length of sides BC is :