20.8g of `BaCI_2` on reaction with 9.8g of `H_2SO_4` produces 7.3 g of HCI and some amount of `BaSO_4` The amount of `BaSO_4` formed is

If the law of conservation of mass was to hold true, then 20.8 g of BaCl_(2) on reaction with 9.8 g of H_(2)SO_(4) will produce 7.3 g of HCl and _______of BaSO_(4)

If law of conservation of mass was to hold true, then 20*8 g of BaCl_(2) on reaction with 9*8 g of H_(2)SO_(4) will produce 7*3 of HCl and BaSO_(4) equal to

20 mL of 0.1 N BaCI_2 is mixed with 30 mL of 0.2 N AI_2 (SO_4)_3 . How many gm of BaSO_4 are formed?

Consider the following reaction BaCl_(2) + H_(2)SO_(4) rarr BaSO_(4) + 2HCl 25 ml of 20.8% (w/v) BaCl_(2) and 50 ml of 9.8 % (w/v) H_(2)SO_(4) are mixd. What is the amount of BaSO_(4) formed.

What volume of 5M Na_2SO_4 must be added to 25 mL of 1M BaCl_2 to produce 10 g of BaSO_4 ?