log(x)4+log(x)16+log(x)64=12...

`log_(x)4+log_(x)16+log_(x)64=12`

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Solve : (ii) log_(x)2log_(x/16)2 = log_(x/64)2 .

log_(16)64-log_(64)16

Solve :3log_(x)(4)+2log_(4x)4+3log_(16x)4=0

Solve : 3log_x(4)+ 2log_(4x)4+3log_(16x)4=0

Solve : 3log_x(4)+ 2log_(4x)4+3log_(16x)4=0

Solve : 3log_x(4)+ 2log_(4x)4+3log_(16x)4=0

If log_(e)2.log_(x)25 = log_(10)16.log_(e )10 , then find the value of x.

If log_(x) 2 log_((x)/(16)) 2 = log_((x)/(64)) 2, then x =

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