Two conductors are made of the same material and have the same length. Conductor `A` is a solid wire of diameter `1 mm`. Conductor `B` is a hollow tube of outer diameter `2 mm` and inner diameter `1mm`. Find the ratio of resistance `R_(A)` to `R_(B)`.

Two conductors arc made of the same material and have the same length. Conductor A is a solid wire of diameter 1 mm. Conductor B is a holJow tube of outer diameter 2 mm and inner diameter lrrun. Find the ratio of resistance R_(A)" to " R_(B) .

Two conductors are made of the same material and have the same length. Conductor A is a solid wire of radius 1.0 mm. Conductor B is a hollow tube of outside radius 2.2 mm and inside radius 1.0 mm. What is the resistance rate R_A//R_B measured between their ends?

Consider two conducting wires of same length and material, one wire is solid with radius r. The other is a hollow tube of outer radius 2r while inner r. The ratio of resistance of the two wires will be -

Two wires A and B have equal lengths and are made of the same material. But the diameter of A is twice that of wire B. Then for a given load

Two wires of the same material and same length have radii 1 mm and 2 mm respectively. Compare : their resistances,

Two solid spheres are made of the same material. The ratio of their diameters is 2: 1. The ratio of their moments of inertia about their respective diameters is

Two conductors made of the same material are connected across a common potential difference. Conductor A has twice the diameter and twice the length of conductor B . The power delivered to the two conductors P_(A) and P_(B) respectively is such that P_(A)//P_(B) equals to