A man of mass 60 kg is in a lift and lift is accelerating upwards with acceleration `4 m//s^(2)`. Calculate effective weight of man in lift.

A man is standing on a weighing machine placed in a lift. When stationary his weight is recorded as 40 kg . If the lift is accelerated upwards with an acceleration of 2m//s^(2) , then the weight recorded in the machine will be (g=10m//s^(2))

A man is standing on a weighing machine placed in a lift. When stationary his weight is recorded as 40 kg . If the lift is accelerated upwards with an acceleration of 2m//s^(2) , then the weight recorded in the machine will be (g=10m//s^(2))

Effective weight of man of mass 50 kg in a lift is 600 N. Lift is accelerating upwards. Calculate acceleration of lift.

Effective weight of man of mass 50 kg in a lift is 600 N. Lift is accelerating upwards. Calculate acceleration of lift.

A man of mass m is on the floor of a lift and lift is moving up with acceleration 'a' then : (a) normal reaction is more than his weight by ma (b) man appears to be heavier by (a/g) times his true weight

A young man of mass 60 kg stands on the floor of a lift which is acceleration downwards at 1m//s^(2) then the reaction of the floor of the lift on the man is (Take g = 9.8 m//s^(2) )

A man of weight W is standing on a lift which is moving upwards with acceleration 'a'. The apparent weight of the man is :

A block of mass 2kg is kept inside a lift. Lift starts moving downward with an acceleration of a=12m/ s^(2) .Height of the lift is 4m .Time after which block will strike roof of the lift is?