Decomposition of `H_(2)O_(2)` is retarded by :
`2H_(2)O_(2)(l) rarr 2H_(2)O(l)+O_(2)(g)`

Decomposition of H_2O_2 is retarded by :

In which of the following reactions At 25^(@)C , does the standard enthalpy change correspond to the standard enthalpy of formation of H_(2)O(l) ? Give reasons. (i) H_(2)(g) +(3)/(2)O_(3)(g) to H_(2)O(l) (ii) H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l) (iii) 2H(g)+O_(2)(g) to H_(2)O(l) .

Calculate Delta H^(theta) for the reaction : H_(2)O (l) rarr H_(2)(g) + (1)/(2) O_(2) (g) Given 2H_(2)(g) + O_(2)(g) rarr 2H_(2)O(l) Delta H = -571.6 kJ

Changes in enthalpy for the reaction : 2H_(2)O_(2)(g) rarr 2H_(2)O (l) + O_(2)(g) if heat of formation of H_(2)O_(2)(l) and H_(2)O(l) are -188 kJ mol^(-1) and -286 kJ mol^(-1) respectively is

Amongst the chemical reaction given below, the reaction with increasing entropy are H_(2)O(l)rarr H_(2)O(g) C(s)+CO_(2)(g)rarr2CO(g) 2H_(2)(g)+O_(2)(g)rarr2H_(2)O(l) N_(2)(g)+O_(2)(g)rarr " Mixture of "N_(2)and O_(2)

Calculate the work done (in J) when 4.5 g of H_(2)O_(2) reacts against a pressure of 1.0 atm at 25^(@)C 2H_(2)O_(2)(l)rarr O_(2)(g) +2H_(2)O(l)

Calculate the work done (in J) when 4.5 g of H_(2)O_(2) reacts against a pressure of 1.0 atm at 25^(@)C 2H_(2)O_(2)(l)rarr O_(2)(g) +2H_(2)O(l)

The standard enthalpies of formation of H_(2)O_(2(l)) and H_(2)O_((l)) are -187.8kJ "mole"^(-1) and -285.8 kJ "mole"^(-1) respectively. The DeltaH^(0) for the decomposition of one mole of H_(2)O_(2(l)) " to" H_(2)O_((l)) and O_(2(g)) is

The standard enthalpies of formation of H_(2)O_(2(l)) and H_(2)O_((l)) are -187.8kJ "mole"^(-1) and -285.8 kJ "mole"^(-1) respectively. The DeltaH^(0) for the decomposition of one mole of H_(2)O_(2(l)) " to" H_(2)O_((l)) and O_(2(g)) is