If `G^2 < G`, which of the following could be G ?

If G be the GM between x and y, then the value of (1)/(G^(2)-x^(2))+(1)/(G^(2)-y^(2)) is equal to (A)G^(2)(B)(2)/(G^(2))(C)(1)/(G^(2))(D)3G^(2)

If G_1 ,G_2 are geometric means , and A is the arithmetic mean between two positive no. then show that G_1^2/G_2+G_2^2/G_1=2A .

If G is the geometric mean of xa n dy then prove that 1/(G^2-x^2)+1/(G^2-y^2)=1/(G^2)

If G is the geometric mean of xa n dy then prove that 1/(G^2-x^2)+1/(G^2-y^2)=1/(G^2)

If G is the geometric mean of x and y then prove that (1)/(G^(2)-x^(2))+(1)/(G^(2)-y^(2))=(1)/(G^(2))

If G is the geometric mean of xa n dy then prove that 1/(G^2-x^2)+1/(G^2-y^2)=1/(G^2)

If G is the geometric mean of xa n dy then prove that 1/(G^2-x^2)+1/(G^2-y^2)=1/(G^2)

If G_1 and G_2 are two geometric means inserted between any two numbers and A is the arithmetic mean of two numbers, then the value of (G_1^2)/G_2+(G_2^2)/G_1 is:

If G_(1) and G_(2) are two geometric means and A is the arithmetic mean inserted two numbers,G_(1)^(2) then the value of (G_(1)^(2))/(G_(2))+(G_(2)^(2))/(G_(1)) is: