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For the redox reaction : Zn(s)+Cu^(2+)...

For the redox reaction :
`Zn(s)+Cu^(2+)(aq) hArr Zn^(2+)(aq)+Cu(s)`
Reaction quotient (Q)`=([Zn^(2+)(aq)])/([Cu^(2+)(aq)])=0.01`. What will be the value of `E_(cell)` ?
Given that OA=1.10 V.

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