If x is a discrete random variable and 'a' is a constant show that
(i) E(a)=a
(ii) E(ax)=aE(x)
(iii) `E(x-barX)=0`

Define a discrete random variable X and its mean E(x) and variance Var(x)

The probability distribution of a discrete random variable X is given as under : Calculate : (i) The value of A if E(X) = 2.94 (ii) Variance of X

Let X be the discrete random variable. Then the variance of X is (a). E(X^2) (b). E(X^2)+(E(X))^2 (c). E(X^2)-(E(X))^2 (d). sqrt(E(X^2)-(E(X))^2)

Two probability distributionof the discrete random variable X and Y are given below. Prove that E(Y^(2))=2E(X) .

Two probability distributionof the discrete random variable X and Y are given below. Prove that E(Y^(2))=2E(X) .

The probability distribution of a discrete random variable x is given as under Calculate (i) the value of A, if E(X)=2.94. (ii) variance of X.

The probability distribution of a discrete random variable x is given as under Calculate (i) the value of A, if E(X)=2.94. (ii) variance of X.

The pobability distribution of a discrete random variable X is given below. If E(X^(2))=Sigma x^(2)P(X=x) , then 6E(X^(2))-Var(X)= {:(X=x,-1,0,1,2,),(P(X=x),1/3,1/6,1/6,1/3,):}

The probability distribution of a discrete random variable x is given by The value 6E(X^(2))-Var(x) is

Two probability distribution of the discrete random variables X and Y are given below: Prove that E(Y^2)=2E(X) .