Two particles P and Q located at distancer, andr, respectively from the centre of a rotating disc such that `r_(P) > r_(Q)`

Two particles p and q located at distances r_p and r_q respectively from the centre of a rotating disc such that r_p gt r_q .

Two particles p and q located at distances r_p and r_q respectively from the centre of a rotating disc such that r_p gt r_q .

Two particles P and Q are located at distance r_(p) and r_(Q) respectively form the centre of rotating disc such that r_(P)gtr_(Q) . The disc is rotating with constant angular acceleration. We can say

Two particles A and B are located at distances r_(A) and r_(B) from the centre of a rotating disc such that r_(A) gt r_(B) . In this case (Angular velocity (omega) of rotation is constant)

Two particles A and B are located at distances r_(A) and r_(B) from the centre of a rotating disc such that r_(A) gt r_(B) . In this case (Angular velocity (omega) of rotation is constant)

The distance between two particles of masses m_(1)andm_(2) is r. If the distance of these particles from the centre of mass of the system are r_(1)andr_(2) respectively, then show that r_(1)=r((m_(2))/(m_(1)+m_(2)))andr_(2)=r((m_(1))/(m_(1)+m_(2)))

Two particles of masses p and q (p gt q) are separated by a distance d . The shift in the centre of mass when the two particles are interchanged is

Two loops P and Q are made from a uniform wire. The radii of P and Q are R_(1) and R_(2) , respectively, and their moments of inertia about their axis of rotation are I_(1) and I_(2) , respectively. If (I_(1))/(I_(2))=4 , then (R_(2))/(R_(1)) is