The latent heat of vaporisation of liquid is `10kcal mol^(-1)` at `1 atm` and `227^(@)C`. What will be the change in internal energy of `3 mol es ` of the liquid at same condition ?

The latent heat of vapourisation of a liquid at 500K and atm pressure is 10kcal mol^(-1) . What will be change in internal energy of 3mol of liquid at same temperature?

The latent heat of vapourisation of a liquid at 500K and atm pressure is 30kcal mol^(-1) . What will be change in internal energy of 3mol of liquid at same temperature?

Latent heat of vaporisation of a liquid at 500 K and 1 atm pressure is 10 kcal//mol . What will be the change in internal energy (DeltaU) of 3 mol of liquid at the same temperature ?

Latent heat of vaporisation of a liquid at 500K and 1 atm pressure is 10.0 kcal//mol . What will be the change in internal energy (DeltaE) of 3 mol of liquid at same temperature?

Latent heat of vaporisation of a liquid at 500K and 1 atm pressure is 10.0 kcal/mol. What will be the change in internal energy (triangleE) of 3 mole of liquid at same temperature:

The latent heat of vaporization of a liquid at 500 K at1atm pressure is 10 kcal/mol. The change in the internal energy of 3 mole of liquid at same temperature will be

Latent heat of vapourisation of a liquid at 500k and 1atm pressure is 10K. Cal/mole. What is the change in internal energy when 3 moles of the liquid is vapourised at the same temperature