For a given reaction, `t_(1//2) = 1 //ka`. The order of this reaction is

For a given reaction t_(1/2)= 1/Ka The order of the reaction is

Fill in the blanks : IF t_1/2 = 1 // ka^2 , then the order of the reaction is ………….

The reaction that obeys the expression t_(1/2) = 1/(Ka) the order of reaction

For a certain reaction involving a single reaction, it is found that C_(0)sqrt(t_(1//2)) is constant where C_(0) is the initial concentration of reactant and t_(1//2) is the half-life. The order of reaction is:

Following is the graph between log t_(1//2) and log a ( a initial concentration) for a given reaction at 27^(@)C . Find the order of reaction.

For 'n' th order reaction, t_(1/2)prop —