An electron `(q = 1.6 × 10^(-19) C)` is moving at right angles to a uniform magnetic field of `3.534 xx10^(-5)` T The time taken by the electron to complete a circular orbit is

In a cyclotron, a position enters prependicular to the magnetic field of induction 3.57 xx 10^(-5)T . What is the time taken by the position to complete a circular orbit? [m_p=9.1 xx 10^(-31)kg and e=1.6 xx 10^(-19)C]

If an electron is moving with a velocity of 10^(-7)m.s^(-1) at right angles to a magnetic field of strength 10^(-3)T , determine the magnetic force acting on the electron and the radius of the circular path it describes. Given, mass of an electron =9.1xx10^(-31)kg , electronic charge =1.6xx10^(-19)C .

A proton is projected with a velocity 10^(7)ms^(-1) , at right angles to a uniform magnetic field of induction 100mT . The time ( in second ) taken by the proton to traverse 90^(@) are is : ( Mass of proton =1.65xx10^(-27)kg an charge of proton =1.6 xx10^(-19)C)

Electron moving at right angle to a uniform magnetic field complete a circular orbit of 10^(-2) m radius in 10^-10s . What is the magnitude of magnetic field.