A body having masss oif 100g is allowed to fall freely under the action of gravity. Calcualate the kinetic energy after 10s. Take g=`9.8ms^(-2)`.

A body having a mass 100 gm is allowed to fall freely under gravity. Calculate KE after 10 seconds g=9.8 m//s^(-2) .

A body having a mass of 100 gm falls freely under the action of gravity. What is the force that acts on it ? Calculate the momentum it possesses after 10 seconds.

A body of masss 1kg is allowed to fall freely under gravity. Find the mimimum and kinetic energy of the body 5 second after it starts falling. Take g= 10 ms^(-2)

A stone at rest is dropped from a height and falls freely under gravity. Calculate the distance covered by it in the first two seconds. (g = 9.8 m s^(-2) )

Calculate the mass of a body weighting 100 N. Take g = 10 ms^-2 .

A body of mass 2kg is resting on a rough horizontal surface. A force of 20N is now applied to it for 10s, parallel to the surface. If the coefficient of kinetic friction between the surfaces of contact is 0.2. Calculate change in kinetic energy of the object in 10s. (Take g=10ms^(-2) ).

A body is dropped freely under gravity from the top of a tower of height 78.4 m. Calculate : (i) the time to reach the ground . Take g = 9.8 m s^(-2) .

Calculate the weight of a body of mass 10 kg in kgf . Take g = 9.8 "m s"^(-2) .

Oif a force 20 N is applied on a body of mass 5 kg at rest then find the kinetic energy of the body after 10s.