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Use a suitable identity to get each of the following products. (i) `(x+3)(x+3)` (ii) `(2y+5)(2y+5)` (iii) `(2a-7)(2a-7)` (iv) `((3a)-1/2)((3a)-1/2)` (v) `(1.1m-0.4)(1.1m+04)` (vi) `(a^2+b^2)(-a^2+b^2)` (viI) `(6x-7)(6x+7)` (vii) `(-a+c)(-a+c)` (viii) `(x/2+(3y)/4)(x/2+((3y)/4)` (ix) `(7a-9b)(7a-9b)`

Text Solution

Verified by Experts

The correct Answer is:
1)`(x+3)(x+3)=x^2+9+6x`
2)`(2y+5)(2y+5)=4y^2+25+20y`
3)`(2a-7)(2a-7)=4a^2+49-28a`
4)`(3a-1/2)(3a-1/2)=9a^2+1/4-3a`
5)`(1.1m-0.4)(1.1m+0.4)=1.21m^2-0.16`
6)`(b^2+a^2)(b^2-a^2)=b^4-a^4`
7)`(6x-7)(6x+7)=36x^2-49`
8)`(x/2+(3y)/4)^2=x^2/4+(9y^2)/16+(3xy)/4`
9)`(7a-9b)^2=49a^2+81b^2-126ab`.
1)`(x+3)(x+3)=x^2+9+6x`
2)`(2y+5)(2y+5)=4y^2+25+20y`
3)`(2a-7)(2a-7)=4a^2+49-28a`
4)`(3a-1/2)(3a-1/2)=9a^2+1/4-3a`
5)`(1.1m-0.4)(1.1m+0.4)=1.21m^2-0.16`
6)`(b^2+a^2)(b^2-a^2)=b^4-a^4`
7)`(6x-7)(6x+7)=36x^2-49`
8)`(x/2+(3y)/4)^2=x^2/4+(9y^2)/16+(3xy)/4`
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