A car of mass `1500kg` is moving with a speed of `12.5ms^(-1)` on a circular path of radius `20m` on a level road What should be the frictional force to avoid slipping of car Calculate the cofficient of friction .

A car of mass 1500 kg is moving with a speed of 12.5 m cdot s^(-1) on a circular path of radius 20 m on a level road. What should be the frictional force between the car and the road so that the car does not slip? What should be the value of the coefficient of friction this force?

A car of mass 1500 kg is moving with a speed of 12.5 ms^(-1) on a circular path of radius 20 m on a level raod what should be the frictional force between the car and the raod so that the car does not slip what should be the value of the coefficent of friction to attain this force

A car of mass 1000 kg is moving with a speed of 40 ms^(-1) on a circular path of radius 400m. If its speed is increasing at the rate of 3ms^(-2) the total force acting on the car is

When a car of 3mass 1000 kg is moving with a velocity of 20ms^(-1) on a rough horizontal road, its engine is switched off. How far does the car move before it comes to rest if the coefficient of kinetic friction between the road and tyres of the car is 0.75 ?