A thin circular loop of radius R rotates about its vertical diameter with an angular frequency `omega` . Show that a small bead on the wire loop remains at its lowermost point for `omegalesqrt(g//R)` . What is the angle made by the radius vector joining the centre to bead with the vertical downward direction for `omega=sqrt(2g//R)` ? Neglect friction .

A thin circular loop of radius R rotates about its vertical diameter with an angular frequency omega . Show that a small bead on the wire loop rem ains at its lowermost point for omega oversetlarrsqrt(g/R) What is the angle made by the radius vector joining the centre to the bead with the vertical downward direction for omega = sqrt (2g/R) ? neglect friction.

A thin circular wire of radius R rotates about its vertical diameter with an angular frequency omega . Show that a small bead on the wire remain at its lowermost point for omegalesqrt(g//R) . What is angle made by the radius vector joining the centre to the bead with the vertical downward direction for omega=sqrt(2g//R) ? Neglect friction.

A thin circular wire of radius R rotates about its vertical diameter with an angular frequency omega . Show that a small bead on the wire remain at its lowermost point for omegalesqrt(g//R) . What is angle made by the radius vector joining the center to the bead with the vertical downward direction for omega=sqrt(2g//R) ? Neglect friction.

A thin circular wire of radius R rotatites about its vertical diameter with an angular frequency omega . Show that a small bead on the wire remain at its lowermost point for omegalesqrt(g//R) . What is angle made by the radius vector joining the centre to the bead with the vertical downward direction for omega=sqrt(2g//R) ? Neglect friction.

A thin circular wire of radius R rotatites about its vertical diameter with an angular frequency omega . Show that a small bead on the wire remain at its lowermost point for omegalesqrt(g//R) . What is angle made by the radius vector joining the centre to the bead with the vertical downward direction for omega=sqrt(2g//R) ? Neglect friction.

A thin circular wire of radius R rotatites about its vertical diameter with an angular frequency omega . Show that a small bead on the wire remain at its lowermost point for omegalesqrt(g//R) . What is angle made by the radius vector joining the centre to the bead with the vertical downward direction for omega=sqrt(2g//R) ? Neglect friction.